worked on hw2 NUCE 2100
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parent
dd2612d0ed
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NUCE_2100/.ipynb_checkpoints/Untitled-checkpoint.ipynb
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140
NUCE_2100/.ipynb_checkpoints/Untitled-checkpoint.ipynb
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{
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"cells": [
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{
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"cell_type": "markdown",
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"id": "153bfedd-a63f-47f7-be65-4d8c006600e4",
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"metadata": {},
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"source": [
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"# Homework 2\n",
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"## NUCE 2100\n",
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"### Dane Sabo\n",
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"\n",
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"---\n",
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"\n",
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"Instructions: Complete the problems below being sure to show your work. If you need to lookup nuclear data from an external source please reference the source in your solutions (once is sufficient).\n",
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"\n",
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"---\n",
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"\n",
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"1. Consider the so-called DT (deuterium, tritium) fusion reaction\n",
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"\n",
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"$^2H + ^3H \\rightarrow ^HHe + ?$\n",
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"\n",
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"a. What is the missing product in the reaction?\n",
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"\n",
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" A neutron!\n",
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"\n",
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"b. Calculate the binding energy of $^2H$, $^{3}H$, and $^{4}He$"
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]
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},
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{
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"cell_type": "code",
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"execution_count": 11,
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"id": "88d5e8eb-f0d6-4397-bcda-98c112bc6bc1",
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"metadata": {},
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"outputs": [
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{
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"name": "stdout",
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"output_type": "stream",
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"text": [
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"2H Binding Energy: -214638011925356.72 mev\n",
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"3H Binding Energy: -818368931224944.4 mev\n",
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"4He Binding Energy: -2730116383379421.0 mev\n"
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]
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}
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],
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"source": [
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"def binding_energy(mass,z,n):\n",
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" c = 299792458 # m/s\n",
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" h1_mass = 1007825.03190 #micro AMU\n",
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" neutron_mass = 1008664.9159 #mirco AMU\n",
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"\n",
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" return (mass - z*h1_mass - n*neutron_mass)/1e6*c**2\n",
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"\n",
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"twoH_mass = 2014101.77784 #micro AMU\n",
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"print(\"2H Binding Energy:\", binding_energy(twoH_mass,1,1), \"mev\")\n",
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"\n",
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"threeH_mass = 3016049.281328 #micro AMU\n",
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"print(\"3H Binding Energy:\", binding_energy(threeH_mass,1,2), \"mev\")\n",
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"\n",
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"fourHe_mass = 4002603.25413 #micro AMU\n",
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"print(\"4He Binding Energy:\", binding_energy(fourHe_mass,2,2), \"mev\")"
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]
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},
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{
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"cell_type": "markdown",
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"id": "6eb8cf35-13c1-44ea-981a-17f9676e5c0e",
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"metadata": {},
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"source": [
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"c. Calculate the Q value of the reaction"
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]
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},
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{
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"cell_type": "code",
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"execution_count": null,
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"id": "ab2b2b84-59bc-4000-9588-b0c0afbb67ae",
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"metadata": {},
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"outputs": [],
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"source": [
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"d. Show that the Q value is equal to the change in binding energy"
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]
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},
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{
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"cell_type": "markdown",
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"id": "e8108f30-f807-4f83-90b8-ce1092404284",
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"metadata": {},
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"source": [
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"2. Using atomic mass data, compute the average binding energy per nucleon of the following\n",
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"nuclei:\n",
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"\n",
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"a. $^{6}Li$\n",
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"\n",
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"b. $^{12}C$\n",
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"\n",
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"c. $^{51}V$\n",
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"\n",
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"d. $^{138}Ba$\n",
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"\n",
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"e. $^{235}U$"
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]
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},
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{
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"cell_type": "markdown",
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"id": "df1603d2-3e2c-463f-93eb-bd9aa1514314",
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"metadata": {},
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"source": [
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"3. Compute the atom densities of $^{235}U$ and $^{238}U$ in UO2 of physical density 10.8 g/cm3 if the uranium\n",
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"is enriched to 3.5 w/o in $^{235}U$."
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]
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},
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{
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"cell_type": "markdown",
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"id": "df698b09-ce8d-4b38-92c7-0d96765e1b25",
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"metadata": {},
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"source": [
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"4. Calculate the mean free path of 1-eV neutrons in graphite. The total cross section of carbon at\n",
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"this energy is 4.8 b."
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]
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}
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],
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"metadata": {
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"kernelspec": {
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"display_name": "Python 3 (ipykernel)",
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"language": "python",
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"name": "python3"
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},
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"language_info": {
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"codemirror_mode": {
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"name": "ipython",
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"version": 3
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},
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"file_extension": ".py",
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"mimetype": "text/x-python",
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"name": "python",
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"nbconvert_exporter": "python",
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"pygments_lexer": "ipython3",
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"version": "3.12.3"
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}
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},
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"nbformat": 4,
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"nbformat_minor": 5
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}
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140
NUCE_2100/Untitled.ipynb
Normal file
140
NUCE_2100/Untitled.ipynb
Normal file
@ -0,0 +1,140 @@
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{
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"cells": [
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{
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"cell_type": "markdown",
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"id": "153bfedd-a63f-47f7-be65-4d8c006600e4",
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"metadata": {},
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"source": [
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"# Homework 2\n",
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"## NUCE 2100\n",
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"### Dane Sabo\n",
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"\n",
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"---\n",
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"\n",
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"Instructions: Complete the problems below being sure to show your work. If you need to lookup nuclear data from an external source please reference the source in your solutions (once is sufficient).\n",
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"\n",
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"---\n",
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"\n",
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"1. Consider the so-called DT (deuterium, tritium) fusion reaction\n",
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"\n",
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"$^2H + ^3H \\rightarrow ^HHe + ?$\n",
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"\n",
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"a. What is the missing product in the reaction?\n",
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"\n",
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" A neutron!\n",
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"\n",
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"b. Calculate the binding energy of $^2H$, $^{3}H$, and $^{4}He$"
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]
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},
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{
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"cell_type": "code",
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"execution_count": 11,
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"id": "88d5e8eb-f0d6-4397-bcda-98c112bc6bc1",
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"metadata": {},
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"outputs": [
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{
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"name": "stdout",
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"output_type": "stream",
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"text": [
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"2H Binding Energy: -214638011925356.72 mev\n",
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"3H Binding Energy: -818368931224944.4 mev\n",
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"4He Binding Energy: -2730116383379421.0 mev\n"
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]
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}
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],
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"source": [
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"def binding_energy(mass,z,n):\n",
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" c = 299792458 # m/s\n",
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" h1_mass = 1007825.03190 #micro AMU\n",
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" neutron_mass = 1008664.9159 #mirco AMU\n",
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"\n",
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" return (mass - z*h1_mass - n*neutron_mass)/1e6*c**2\n",
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"\n",
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"twoH_mass = 2014101.77784 #micro AMU\n",
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"print(\"2H Binding Energy:\", binding_energy(twoH_mass,1,1), \"mev\")\n",
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"\n",
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"threeH_mass = 3016049.281328 #micro AMU\n",
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"print(\"3H Binding Energy:\", binding_energy(threeH_mass,1,2), \"mev\")\n",
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"\n",
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"fourHe_mass = 4002603.25413 #micro AMU\n",
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"print(\"4He Binding Energy:\", binding_energy(fourHe_mass,2,2), \"mev\")"
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]
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},
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{
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"cell_type": "markdown",
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"id": "6eb8cf35-13c1-44ea-981a-17f9676e5c0e",
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"metadata": {},
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"source": [
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"c. Calculate the Q value of the reaction"
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]
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},
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{
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"cell_type": "code",
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"execution_count": null,
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"id": "ab2b2b84-59bc-4000-9588-b0c0afbb67ae",
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"metadata": {},
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"outputs": [],
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"source": [
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"d. Show that the Q value is equal to the change in binding energy"
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]
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},
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{
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"cell_type": "markdown",
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"id": "e8108f30-f807-4f83-90b8-ce1092404284",
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"metadata": {},
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"source": [
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"2. Using atomic mass data, compute the average binding energy per nucleon of the following\n",
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"nuclei:\n",
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"\n",
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"a. $^{6}Li$\n",
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"\n",
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"b. $^{12}C$\n",
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"\n",
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"c. $^{51}V$\n",
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"\n",
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"d. $^{138}Ba$\n",
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"\n",
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"e. $^{235}U$"
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]
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},
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{
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"cell_type": "markdown",
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"id": "df1603d2-3e2c-463f-93eb-bd9aa1514314",
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"metadata": {},
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"source": [
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"3. Compute the atom densities of $^{235}U$ and $^{238}U$ in UO2 of physical density 10.8 g/cm3 if the uranium\n",
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"is enriched to 3.5 w/o in $^{235}U$."
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]
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},
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{
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"cell_type": "markdown",
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"id": "df698b09-ce8d-4b38-92c7-0d96765e1b25",
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"metadata": {},
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"source": [
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"4. Calculate the mean free path of 1-eV neutrons in graphite. The total cross section of carbon at\n",
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"this energy is 4.8 b."
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]
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}
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],
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"metadata": {
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"kernelspec": {
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"display_name": "Python 3 (ipykernel)",
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"language": "python",
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"name": "python3"
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},
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"language_info": {
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"codemirror_mode": {
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"name": "ipython",
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"version": 3
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},
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"file_extension": ".py",
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"mimetype": "text/x-python",
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"name": "python",
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"nbconvert_exporter": "python",
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"pygments_lexer": "ipython3",
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"version": "3.12.3"
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}
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},
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"nbformat": 4,
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"nbformat_minor": 5
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}
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