1.8 KiB
What is a limit cycle?
Isolated, closed trajectories.
- Not like a center.
- Centers are closed, but not isolated.
- Neighboring trajectories are NOT closed. Different forms:
- Stable - Trajectories pull onto the limit cycle
- Unstable - Trajectories are repelled by the limit cycle.
A imit cycle is a explicitly nonlinear phenomenon.
You can't identify if there is a limit cycle by using linearizing methods.
How do we find limit cycles?
How do we rule out a closed loop?
Dulac's Criterion:
If we have some flow field:
\dot{\vec{x}}= f(\vec x)
- If we can find a function
\zeta(x,y)such that\nabla \cdot (\zeta f))does not change sign in some region ofR, then there's no limit cycle in that region. - If in some region
R,\zeta(x,y)s.t :\frac{\partial}{\partial x} (\zeta(x,y) f_1(x,y)) + \frac{\partial}{\partial y}(\zeta(x,y) f_2(x,y))is of constant sign, then there are no closed orbits in R. Finding\zetais tricky.
Example:
\dot x = y
\dot y = -x -y + x^2 + y^2
Assume \zeta(x,y) = 1
\partial / \partial x (y) + \partial / \partial y (-x - y +x^2 +y^2) /rightarrow 0 + (-1+2y)
Assume \zeta(x,y) = e^{\alpha x}
\partial / \partial x (e^{\alpha x} y) + \partial / \partial y (e^{\alpha x} (-x - y +x^2 +y^2))
\alpha e^{\alpha x} y + 2 y e^{\alpha x} - e^{\alpha x}
e^{\alpha x}((\alpha+2) y -1)
Now let \alpha = -2
\nabla \cdot (\zeta f) = e^{-2 x}
Now a special note: These functions can define where limit cycles can't be. If the function doesn't change sign for a subset of R, there can't be a limit cycle contained in that subset. There CAN be a limit cycle that crosses the point the function changes sign.
Lyapunov Function
Aleksander Lyapunov (Liapunov)