vault backup: 2024-09-30 13:30:32

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Dane Sabo 2024-09-30 13:30:32 -04:00
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@ -39,3 +39,21 @@ $\nabla \cdot (\zeta f) = e^{-2 x}$
Now a special note: These functions can define where limit cycles can't be. If the function doesn't change sign for a subset of R, there can't be a limit cycle contained in that subset. There CAN be a limit cycle that crosses the point the function changes sign. Now a special note: These functions can define where limit cycles can't be. If the function doesn't change sign for a subset of R, there can't be a limit cycle contained in that subset. There CAN be a limit cycle that crosses the point the function changes sign.
### Lyapunov Function ### Lyapunov Function
Aleksander Lyapunov (Liapunov) Aleksander Lyapunov (Liapunov)
$V(\vec x) = V(x,y) \leftarrow$ a scalar function
$V(\vec x) > 0 \forall \vec x\neq \vec x^*$
$V(\vec x^*) = 0$
$\dot V = \frac{dV}{dt} <0$
$V(\vec x)$ is a positive definite function.
Then the system is stable ISL (in the sense of Lyapunov).
The system will always asymptotically approach the equilibrium point.
$\frac{dV}{dt} = \frac{dV}{dx} \frac{dx}{dt} + \frac{dV}{dy} \frac {dy}{dt} = \dot x \frac{dV}{dx} + \dot y \frac{dV}{dy}$
Example:
$\dot x = y - x^3$
$\dot y = -x-y^3$
$V(x,y) = c_1 x^2 + c_2 y^2$
$\frac{dV}{dt} = 2 c_1 x \dot x + 2 c_2 y \dot y$
$= 2 c_1 x(y-x^3) + 2c_2 y(-x-y^3)$
Assume $c_1 = c_2$
... $\therefore \frac{dV}{dt} = -2c(x^4+y^4) < 0$
Therefore limit cycles are not possible.