Attendance: Dane Sabo and David Pabst
January 21st, 2025

# Question 1.1
What happens to the Direct output signal if the terminator is not connected to the attenuated output of the pulser?
A: To start, time scale is 400 microseconds, delta of 1.4V 
attenuatrion switches
normal operating shape is exponential decay after an impulse. 4V
Now, removing attenuatrion plug. No change
Removing the plug on the cable connected to oscilloscope, doubled magnitude of signal
The only thing that changes is the slope of the pulse decay. Is also dependent on attenuation. No impedence on the attenuated port results in less severse slope
This is a result of the impedence on the attenuated side. If all attenuation is on, it is effectively very high impedence just like the oscilloscope. No attenuation is low impedence, and therefore it isn't matched

Exercises 1.1 and 1.2 are pictures taken
Exercise 1.3

| Attenuation | Voltage |
| ----------- | ------- |
| 1000/1000   | 5.44V   |
| 800/1000    | 4.42V   |
| 600/1000    | 3.38V   |
| 400/1000    | 2.30V   |
| 200/1000    | 1.24V   |

- [x] Do exercise 1.4 where we make a linear relationsihp of above data #NUCE2113 🔼 ⏳ 2025-01-27 📅 2025-01-28 ✅ 2025-01-27

| Attenuation Switches | Voltage |
| -------------------- | ------- |
| All 1x               | 4.00 V  |
| 2x                   | 2.10 V  |
| 5x                   | 0.94 V  |
| 10x                  | 0.398 V |
| 2x 5s                | 0.400 V |
Third column is needed to compare measured voltage to 1x voltage
